A - addend 中文

addend n.【數學】加數。

First , with the coding idea of thomas h . labean “ logical computation using dna molecules “ , we developed a dna - based addition model of two n - system addend 首先，運用labean解決累加異或問題的編碼思想，實現n進制的兩個加數的加法進位問題。
addendum
When xiaolangdi project completed and put into orperation , the inflow of water and sediment condition will be changed because of the regulation of the reservoir . especially the initial 14 years , the reservoir will hold up sediment and release clear water , which may affect the river sections in henan province , especially the wandering sections . it will result in changes of flow state and endangering the water works , because the longitudinal addend by scouring and lateral slope failure 小浪底水庫建成運用后，通過水庫的調水調沙，改變了黃河下游的來水來沙條件，尤其是運用的前14年處于攔沙期，下泄清水，對河南河道的影響最為劇烈，對游蕩性河段的河勢變化將產生很大影響，河道縱向沖刷下切，橫向灘岸坍塌，工程出險將大量增加。
This arithmetic cast off serial addition idea , but entirely enumerate every pair of addends on a bit . and it also calculate two possible receiving carry value on each bit . so the addition can be operated through automatic selection , and complete collateral addition and carry operation 這種算法擺脫了以往的串行加法運算思想，將每一位上兩個加數對的所有可能進行全列舉，同時考慮每一位上接受進位值的兩種可能，使得加法運算在自動進行選擇的過程中完成并行的加法和進位。
Numeral switch warehouse is the kernel of this algorithmic . with the idea of entirely enumeration , we make each bit coded for different system switching , and the coding satisfied definite rule which cause each bit arbitrary can link in order . the third is about dna - based computation model of multi - addend success addition 數制轉換庫的結構和分子的設計編碼是這個算法的核心，利用全列舉的思想，將不同數制互換時的對應進制級分別編碼，編碼滿足一定的規則，這種規則使得各個進制級可以任意順次連接，并且唯一的對應著轉換得到的不同進制的數。
First , with the coding idea of thomas h . labean “ logical computation using dna molecules “ , we developed a dna - based addition model of two n - system addend 首先，運用labean解決累加異或問題的編碼思想，實現n進制的兩個加數的加法進位問題。
The way to find an unknown addend from one addend and the sum is called subtraction . this is the essence of subtraction . please read after me 歸納減法的意義：已知兩個加數的和與其中的一個加數，求另一個加數的運算，叫做減法。（讓學生讀讀。）
This demonstrates the operation addition performed on two whole numbers , two and three ( known as addends , ) which result in a sum ( total ) of five circles 以上演示了兩個整數的加法運算，兩個整數分別為2和3 （是作為加數），這樣就得到和是5個球。
One addend adds one number . the other addend subtracts the same number . the sums are the same 小結：一個加數增加幾，另一個加數減少幾，增加和減少的數相等，它們的和仍是10 。
Subtract one addend from the sum . if you can get the other addend , you ' re right 加法的驗算。從算出的和里減去一個加數，看是不是等于另一個加數。
In addition , add the addends in any order and the sum remains the same 師：這就是加法結合律。利用加法結合律，可以進行簡便運算。請做下列題。
Multiplication is the easier way to find the sum of same addends 根據學生的回答總結得出：求幾個相同加數的和的簡便運算，叫做乘法。
The two numbers being added are the addends . the answer is the sum 3電腦出示結論：相加的兩個數叫做加數，加的數叫做和。
137 and 357 are the addends . the answer 494 is the sum 生： 137和357在加法算式中叫做加數。他們相加的得數494叫做和。
In addition , switch the two addends and the sum remains the same 生：兩個數相加，交換加數的位置，他們的和不變。
Switch the two addends and the sum remains the same 7生：兩個數相加，交換加數的位置，他們的和不變。
Stability of multiplier - addend model and the macro - control policies 加速數模型的穩定性與宏觀調控政策
Switch the two addends and the sum remains the same 生：交換兩個加數的位置，和不變。
Thus, the augend and the addend must each be small enough to fit within one memory location . 由此可見，加數和被加數都應足夠小，以便能夠合適地裝入一個存儲單元。
Thus, the augend and addend must each be small enough to fit within one memory location . 由此可見，加數和被加數都應足夠小，以便能夠適合地裝入一個存儲單元。

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addend

addend n.【數學】加數。

First , with the coding idea of thomas h . labean “ logical computation using dna molecules “ , we developed a dna - based addition model of two n - system addend 首先，運用labean解決累加異或問題的編碼思想，實現n進制的兩個加數的加法進位問題。

addendum

First , with the coding idea of thomas h . labean “ logical computation using dna molecules “ , we developed a dna - based addition model of two n - system addend 首先，運用labean解決累加異或問題的編碼思想，實現n進制的兩個加數的加法進位問題。

The way to find an unknown addend from one addend and the sum is called subtraction . this is the essence of subtraction . please read after me 歸納減法的意義：已知兩個加數的和與其中的一個加數，求另一個加數的運算，叫做減法。 （讓學生讀讀。 ）

This demonstrates the operation addition performed on two whole numbers , two and three ( known as addends , ) which result in a sum ( total ) of five circles 以上演示了兩個整數的加法運算，兩個整數分別為2和3 （是作為加數） ，這樣就得到和是5個球。

One addend adds one number . the other addend subtracts the same number . the sums are the same 小結：一個加數增加幾，另一個加數減少幾，增加和減少的數相等，它們的和仍是10 。

Subtract one addend from the sum . if you can get the other addend , you ' re right 加法的驗算。從算出的和里減去一個加數，看是不是等于另一個加數。

In addition , add the addends in any order and the sum remains the same 師：這就是加法結合律。利用加法結合律，可以進行簡便運算。請做下列題。

Multiplication is the easier way to find the sum of same addends 根據學生的回答總結得出：求幾個相同加數的和的簡便運算，叫做乘法。

The two numbers being added are the addends . the answer is the sum 3電腦出示結論：相加的兩個數叫做加數，加的數叫做和。

137 and 357 are the addends . the answer 494 is the sum 生： 137和357在加法算式中叫做加數。他們相加的得數494叫做和。

In addition , switch the two addends and the sum remains the same 生：兩個數相加，交換加數的位置，他們的和不變。

Switch the two addends and the sum remains the same 7生：兩個數相加，交換加數的位置，他們的和不變。

Stability of multiplier - addend model and the macro - control policies 加速數模型的穩定性與宏觀調控政策

Switch the two addends and the sum remains the same 生：交換兩個加數的位置，和不變。

Thus, the augend and the addend must each be small enough to fit within one memory location . 由此可見，加數和被加數都應足夠小，以便能夠合適地裝入一個存儲單元。

Thus, the augend and addend must each be small enough to fit within one memory location . 由此可見，加數和被加數都應足夠小，以便能夠適合地裝入一個存儲單元。

The way to find an unknown addend from one addend and the sum is called subtraction . this is the essence of subtraction . please read after me 歸納減法的意義：已知兩個加數的和與其中的一個加數，求另一個加數的運算，叫做減法。（讓學生讀讀。）

This demonstrates the operation addition performed on two whole numbers , two and three ( known as addends , ) which result in a sum ( total ) of five circles 以上演示了兩個整數的加法運算，兩個整數分別為2和3 （是作為加數），這樣就得到和是5個球。